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750=-16t^2+220t
We move all terms to the left:
750-(-16t^2+220t)=0
We get rid of parentheses
16t^2-220t+750=0
a = 16; b = -220; c = +750;
Δ = b2-4ac
Δ = -2202-4·16·750
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-220)-20}{2*16}=\frac{200}{32} =6+1/4 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-220)+20}{2*16}=\frac{240}{32} =7+1/2 $
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